What is the extreme f(x)=6x^2+2,1<= x<= 2 ?

The extreme f(x)=6x^2+2,1<= x<= 2 is Minimum(1,8),Maximum(2,26)

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extreme f(x)=6x^2+2,1<= x<= 2

extreme

Minimum (1, 8), Maximum (2, 26)

Solution steps

Find the critical points:

x = 1, x = 2

Domain of

6 x^{2} + 2, 1 \leq x \leq 2 : 1 \leq x \leq 2

Find intervals:

Increasing

: 1 < x < 2

Plug the extreme point

x = 1

into

6 x^{2} + 2 \Rightarrow y = 8

Minimum (1, 8)

Plug the extreme point

x = 2

into

6 x^{2} + 2 \Rightarrow y = 26

Maximum (2, 26)

Minimum (1, 8), Maximum (2, 26)

What is the extreme f(x)=6x^2+2,1<= x<= 2 ?
The extreme f(x)=6x^2+2,1<= x<= 2 is Minimum(1,8),Maximum(2,26)