What is the extreme f(x)=-0.03x^2+300x-100000 ?

The extreme f(x)=-0.03x^2+300x-100000 is Maximum(5000,650000)

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extreme f(x)=-0.03x^2+300x-100000

extreme

Maximum (5000, 650000)

Solution steps

f^{'} (x) = - 0.06 x + 300

Find intervals:

Increasing

: - \infty < x < 5000,

Decreasing

: 5000 < x < \infty

Plug

x = 5000

into

- 0.03 x^{2} + 300 x - 100000 : 650000

Maximum (5000, 650000)

What is the extreme f(x)=-0.03x^2+300x-100000 ?
The extreme f(x)=-0.03x^2+300x-100000 is Maximum(5000,650000)