extreme y=(x^2)/(x^2+243)

Lösung

extrempunkte

y = \frac{x ^{2}}{x ^{2} + 243}

Minimum (0, 0)

Schritte zur Lösung

f^{'} (x) = \frac{486 x}{( x ^{2} + 243 ) ^{2}}

Intervalle finden:

Absteigend

: - \infty < x < 0,

Ansteigend

: 0 < x < \infty

Stecke

x = 0

\frac{x ^{2}}{x ^{2} + 243} : 0

Minimum (0, 0)

e x t re m e f (x) = 2 x^{2} - 8 x y + 10 y^{2} + 10 x - 4 y - 5

e x t re m e f (x) = 2 x^{4} - 8 x^{3} + 4

e x t re m e f (x, y) = 448 x + 233 y + x y - 2 x^{2} - 3 y^{2} - 15438

e x t re m e f (x) = \frac{2 x}{x ^{2} + 3}, - 4 \leq x \leq 0

e x t re m e f (x) = \frac{x e ^{x}}{4 - x}