What is the extreme f(x)=2x^4-8x^3+4 ?

The extreme f(x)=2x^4-8x^3+4 is Saddle(0,4),Minimum(3,-50)

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extreme f(x)=2x^4-8x^3+4

extreme

Saddle (0, 4), Minimum (3, - 50)

Solution steps

f^{'} (x) = 8 x^{3} - 24 x^{2}

Find intervals:

Decreasing

: - \infty < x < 0,

Decreasing

: 0 < x < 3,

Increasing

: 3 < x < \infty

Plug

x = 0

into

2 x^{4} - 8 x^{3} + 4 : 4

Saddle (0, 4)

Plug

x = 3

into

2 x^{4} - 8 x^{3} + 4 : - 50

Minimum (3, - 50)

Saddle (0, 4), Minimum (3, - 50)

What is the extreme f(x)=2x^4-8x^3+4 ?
The extreme f(x)=2x^4-8x^3+4 is Saddle(0,4),Minimum(3,-50)