extreme f(x)=355x^2-1420x^3

Lösung

extrempunkte

f (x) = 355 x^{2} - 1420 x^{3}

Minimum (0, 0), Maximum (\frac{1}{6}, \frac{355}{108})

Schritte zur Lösung

f^{'} (x) = 710 x - 4260 x^{2}

Intervalle finden:

Absteigend

: - \infty < x < 0,

Ansteigend

: 0 < x < \frac{1}{6},

Absteigend

: \frac{1}{6} < x < \infty

Stecke

x = 0

355 x^{2} - 1420 x^{3} : 0

Minimum (0, 0)

Stecke

x = \frac{1}{6}

355 x^{2} - 1420 x^{3} : \frac{355}{108}

Maximum (\frac{1}{6}, \frac{355}{108})

Minimum (0, 0), Maximum (\frac{1}{6}, \frac{355}{108})

e x t re m e f (x) = 6 x^{2} - 6

e x t re m e f (x) = 4 x^{3} - 16

e x t re m e f (x) = - 7 x^{\frac{5}{3}} + 2 3 x

e x t re m e f (x, y) = 2 x^{2} - 4 y + y^{2}

e x t re m e f (x) = 3 x + 4 32.5 - x^{2}