What is the extreme 2x^3-x^2-4x+4 ?

The extreme 2x^3-x^2-4x+4 is Maximum(-2/3 , 152/27),Minimum(1,1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

extreme 2x^3-x^2-4x+4

extreme

Maximum (- \frac{2}{3}, \frac{152}{27}), Minimum (1, 1)

Solution steps

f^{'} (x) = 6 x^{2} - 2 x - 4

Find intervals:

Increasing

: - \infty < x < - \frac{2}{3},

Decreasing

: - \frac{2}{3} < x < 1,

Increasing

: 1 < x < \infty

Plug

x = - \frac{2}{3}

into

2 x^{3} - x^{2} - 4 x + 4 : \frac{152}{27}

Maximum (- \frac{2}{3}, \frac{152}{27})

Plug

x = 1

into

2 x^{3} - x^{2} - 4 x + 4 : 1

Minimum (1, 1)

Maximum (- \frac{2}{3}, \frac{152}{27}), Minimum (1, 1)

What is the extreme 2x^3-x^2-4x+4 ?
The extreme 2x^3-x^2-4x+4 is Maximum(-2/3 , 152/27),Minimum(1,1)