extreme 2x^3-x^2-4x+4

Lösung

extrempunkte

2 x^{3} - x^{2} - 4 x + 4

Maximum (- \frac{2}{3}, \frac{152}{27}), Minimum (1, 1)

Schritte zur Lösung

f^{'} (x) = 6 x^{2} - 2 x - 4

Intervalle finden:

Ansteigend

: - \infty < x < - \frac{2}{3},

Absteigend

: - \frac{2}{3} < x < 1,

Ansteigend

: 1 < x < \infty

Stecke

x = - \frac{2}{3}

2 x^{3} - x^{2} - 4 x + 4 : \frac{152}{27}

Maximum (- \frac{2}{3}, \frac{152}{27})

Stecke

x = 1

2 x^{3} - x^{2} - 4 x + 4 : 1

Minimum (1, 1)

Maximum (- \frac{2}{3}, \frac{152}{27}), Minimum (1, 1)

e x t re m e f (x, y) = \frac{2}{x} + \frac{1}{y} + x y

e x t re m e f (x) = 26 x^{2} + 80 x + 64

e x t re m e f (x, y) = x^{3} - y^{2} - 12 x + 4 y + 2

e x t re m e f (x) = - 3 sin^{2} (x), 0 \leq x \leq π

e x t re m e x^{2} + 2