extreme f(x)= 4/3 x^2-4x

Lösung

extrempunkte

f (x) = \frac{4}{3} x^{2} - 4 x

Minimum (\frac{3}{2}, - 3)

Schritte zur Lösung

f^{'} (x) = \frac{8 x}{3} - 4

Intervalle finden:

Absteigend

: - \infty < x < \frac{3}{2},

Ansteigend

: \frac{3}{2} < x < \infty

Stecke

x = \frac{3}{2}

\frac{4}{3} x^{2} - 4 x : - 3

Minimum (\frac{3}{2}, - 3)

e x t re m e f (x) = x^{5} - 10 x^{4} + 2 = x^{4} (x - 10) + 2

e x t re m e f (x) = x^{9} - x^{7}

e x t re m e 3 x^{4} + 3 y^{4} - 2 x y

e x t re m e f (x) = 150 x + 18 x^{2} - 1.5 x^{3}

e x t re m e f (x) = sin^{2} (2 x) - cos^{2} (2 x) - 1