extreme (4x)/(x^2+4)

Lösung

extrempunkte

\frac{4 x}{x ^{2} + 4}

Minimum (- 2, - 1), Maximum (2, 1)

Schritte zur Lösung

f^{'} (x) = \frac{4 ( - x ^{2} + 4 )}{( x ^{2} + 4 ) ^{2}}

Intervalle finden:

Absteigend

: - \infty < x < - 2,

Ansteigend

: - 2 < x < 2,

Absteigend

: 2 < x < \infty

Stecke

x = - 2

\frac{4 x}{x ^{2} + 4} : - 1

Minimum (- 2, - 1)

Stecke

x = 2

\frac{4 x}{x ^{2} + 4} : 1

Maximum (2, 1)

Minimum (- 2, - 1), Maximum (2, 1)

e x t re m e f (x) = - 0.018 x^{3} + 0.215 x^{2} + 0.057 x + 1

e x t re m e f (x) = 2 x^{3} + 9 x^{2} - 60 x + 7, - 5 \leq x \leq 5

e x t re m e f (x) = (x + 2)^{2} (x - 3)^{3}

e x t re m e f (x, y) = - 2 x^{2} + 5 y^{2} - 9 x + 9 y + 6

e x t re m e f (x) = x^{3} + y^{2} - 3 x - 4 y + 7