extreme y=x^{4/7}(11/4+x)

Lösung

extrempunkte

y = x^{\frac{4}{7}} (\frac{11}{4} + x)

Maximum (- 1, \frac{7}{4}), Minimum (0, 0)

Schritte zur Lösung

f^{'} (x) = \frac{11 ( x + 1 )}{7 x ^{\frac{3}{7}}}

Intervalle finden:

Ansteigend

: - \infty < x < - 1,

Absteigend

: - 1 < x < 0,

Ansteigend

: 0 < x < \infty

Stecke

x = - 1

x^{\frac{4}{7}} (\frac{11}{4} + x) : \frac{7}{4}

Maximum (- 1, \frac{7}{4})

Stecke

x = 0

x^{\frac{4}{7}} (\frac{11}{4} + x) : 0

Minimum (0, 0)

Maximum (- 1, \frac{7}{4}), Minimum (0, 0)

e x t re m e f (x) = ln (x^{2} + 9)

e x t re m e \frac{1}{3} x^{3} + 2 x^{2} + 4 x + 1

e x t re m e f (x) = x^{6} - x^{4}

e x t re m e f (x, y) = 3 x^{(4)} y^{(5)} + 6 x - 7 y

e x t re m e \frac{4 x}{x ^{2} + 4}