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Popular Functions >

extreme f(x)=ln(x^2+9)

Solution

extreme

Solution

Minimum (0, 2 ln (3))

Solution steps

f^{'} (x) = \frac{2 x}{x ^{2} + 9}

Find intervals:

Decreasing

: - \infty < x < 0,

Increasing

: 0 < x < \infty

Plug

x = 0

into

ln (x^{2} + 9) : 2 ln (3)

Minimum (0, 2 ln (3))

Graph

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Frequently Asked Questions (FAQ)

What is the extreme f(x)=ln(x^2+9) ?
The extreme f(x)=ln(x^2+9) is Minimum(0,2ln(3))