extreme f(x)=250+8x^3+x^4

Lösung

extrempunkte

f (x) = 250 + 8 x^{3} + x^{4}

Minimum (- 6, - 182), Sattel (0, 250)

Schritte zur Lösung

f^{'} (x) = 4 x^{3} + 24 x^{2}

Intervalle finden:

Absteigend

: - \infty < x < - 6,

Ansteigend

: - 6 < x < 0,

Ansteigend

: 0 < x < \infty

Stecke

x = - 6

250 + 8 x^{3} + x^{4} : - 182

Minimum (- 6, - 182)

Stecke

x = 0

250 + 8 x^{3} + x^{4} : 250

Sattel (0, 250)

Minimum (- 6, - 182), Sattel (0, 250)

e x t re m e f (x, y) = \frac{x + 4}{y ^{2} - x ^{2}}

e x t re m e f (x, y) = (x - 1)^{2} + y^{3} - 3 y^{2} - 9 y + 5

e x t re m e f (x) = 3 cos (3 x) + sin (3 x)

e x t re m e f (x, y) = x^{2} + 3 x y + y^{2} + 5 x - 7 y

e x t re m e f (x) = \frac{3 - 9 - x ^{2}}{x}