What is the extreme f(x)=x^2+xy+1/2 y^2-2x+y ?

The extreme f(x)=x^2+xy+1/2 y^2-2x+y is Minimum(3,-4)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

extreme f(x)=x^2+xy+1/2 y^2-2x+y

extreme

Minimum (3, - 4)

Solution steps

Find the critical points:

(3, - 4)

\frac{\partial ^{2} f}{\partial x ^{2}} = 1

D (x, y) = 1

Check the sign of at each critical point

Check critical point

(3, - 4) :

Minimum

Minimum (3, - 4)

What is the extreme f(x)=x^2+xy+1/2 y^2-2x+y ?
The extreme f(x)=x^2+xy+1/2 y^2-2x+y is Minimum(3,-4)