What is the extreme y=x^3-30x^2+6000 ?

The extreme y=x^3-30x^2+6000 is Maximum(0,6000),Minimum(20,2000)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

extreme y=x^3-30x^2+6000

extreme

Maximum (0, 6000), Minimum (20, 2000)

Solution steps

f^{'} (x) = 3 x^{2} - 60 x

Find intervals:

Increasing

: - \infty < x < 0,

Decreasing

: 0 < x < 20,

Increasing

: 20 < x < \infty

Plug

x = 0

into

x^{3} - 30 x^{2} + 6000 : 6000

Maximum (0, 6000)

Plug

x = 20

into

x^{3} - 30 x^{2} + 6000 : 2000

Minimum (20, 2000)

Maximum (0, 6000), Minimum (20, 2000)

What is the extreme y=x^3-30x^2+6000 ?
The extreme y=x^3-30x^2+6000 is Maximum(0,6000),Minimum(20,2000)