What is the extreme f(x)=-x^3+12x-8 ?

The extreme f(x)=-x^3+12x-8 is Minimum(-2,-24),Maximum(2,8)

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extreme f(x)=-x^3+12x-8

extreme

Minimum (- 2, - 24), Maximum (2, 8)

Solution steps

f^{'} (x) = - 3 x^{2} + 12

Find intervals:

Decreasing

: - \infty < x < - 2,

Increasing

: - 2 < x < 2,

Decreasing

: 2 < x < \infty

Plug

x = - 2

into

- x^{3} + 12 x - 8 : - 24

Minimum (- 2, - 24)

Plug

x = 2

into

- x^{3} + 12 x - 8 : 8

Maximum (2, 8)

Minimum (- 2, - 24), Maximum (2, 8)

What is the extreme f(x)=-x^3+12x-8 ?
The extreme f(x)=-x^3+12x-8 is Minimum(-2,-24),Maximum(2,8)