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Popular Functions >

inverse of 3/(s^2+9)

Solution

inverse

\frac{3}{s ^{2} + 9}

Solution

\frac{3 - 9 s}{s}, - \frac{3 - 9 s}{s}

Solution steps

y = \frac{3}{s ^{2} + 9}

Replace

s

with

y

s = \frac{3}{y ^{2} + 9}

Solve for

y, s = \frac{3}{y ^{2} + 9}

\frac{3 - 9 s}{s}, - \frac{3 - 9 s}{s}

Graph

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Frequently Asked Questions (FAQ)

What is the inverse of 3/(s^2+9) ?
The inverse of 3/(s^2+9) is sqrt((3-9s)/s),-sqrt((3-9s)/s)