What is the inverse of f(x)= 39/10 t^2 ?

The inverse of f(x)= 39/10 t^2 is sqrt((10t)/(39)),-sqrt((10t)/(39))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

inverse of f(x)= 39/10 t^2

inverse

f (x) = \frac{39}{10} t^{2}

\frac{10 t}{39}, - \frac{10 t}{39}

Solution steps

x = \frac{39}{10} t^{2}

Replace

t

with

x

t = \frac{39}{10} x^{2}

Solve for

x, t = \frac{39}{10} x^{2}

\frac{10 t}{39}, - \frac{10 t}{39}

What is the inverse of f(x)= 39/10 t^2 ?
The inverse of f(x)= 39/10 t^2 is sqrt((10t)/(39)),-sqrt((10t)/(39))