What is the inverse of (x-1)/(x^2+3x+2) ?

The inverse of (x-1)/(x^2+3x+2) is (-3x+1+sqrt(x^2-10x+1))/(2x),(-3x+1-sqrt(x^2-10x+1))/(2x)

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inverse of (x-1)/(x^2+3x+2)

inverse

\frac{x - 1}{x ^{2} + 3 x + 2}

\frac{- 3 x + 1 + x ^{2} - 10 x + 1}{2 x}, \frac{- 3 x + 1 - x ^{2} - 10 x + 1}{2 x}

Solution steps

y = \frac{x - 1}{x ^{2} + 3 x + 2}

Replace

x

with

y

x = \frac{y - 1}{y ^{2} + 3 y + 2}

Solve for

y, x = \frac{y - 1}{y ^{2} + 3 y + 2}

\frac{- 3 x + 1 + x ^{2} - 10 x + 1}{2 x}, \frac{- 3 x + 1 - x ^{2} - 10 x + 1}{2 x}

What is the inverse of (x-1)/(x^2+3x+2) ?
The inverse of (x-1)/(x^2+3x+2) is (-3x+1+sqrt(x^2-10x+1))/(2x),(-3x+1-sqrt(x^2-10x+1))/(2x)