en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

distance (2,8),(4,5)

Solution

distance

(2, 8), (4, 5)

Solution

13

Solution steps

The distance between

(x_{1}, y_{1}), (x_{2}, y_{2})

is:

(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}

The distance between

(2, 8)

and

(4, 5)

is

= (4 - 2)^{2} + (5 - 8)^{2}

Simplify

= 13

Popular Examples

domain of f(x)=ln(x^2-4)domain

f (x) = ln (x^{2} - 4)

distance (4,-3),(-2,-3)distance

(4, - 3), (- 2, - 3)

inverse of 6/(7+x)inverse

\frac{6}{7 + x}

symmetry-1/4 x^3 symmetry

- \frac{1}{4} x^{3}

distance (13/3 , 1/7),(1/3 , 8/7)distance

(\frac{13}{3}, \frac{1}{7}), (\frac{1}{3}, \frac{8}{7})

Frequently Asked Questions (FAQ)

What is the distance (2,8),(4,5) ?
The distance (2,8),(4,5) is square root of 13