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Popular >

distance (4,-3),(-2,-3)

Solution

distance

(4, - 3), (- 2, - 3)

Solution

6

Solution steps

The distance between

(x_{1}, y_{1}), (x_{2}, y_{2})

is:

(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}

The distance between

(4, - 3)

and

(- 2, - 3)

is

= (- 2 - 4)^{2} + (- 3 - (- 3))^{2}

Simplify

= 6

Popular Examples

inverse of 6/(7+x)inverse

\frac{6}{7 + x}

symmetry-1/4 x^3 symmetry

- \frac{1}{4} x^{3}

distance (13/3 , 1/7),(1/3 , 8/7)distance

(\frac{13}{3}, \frac{1}{7}), (\frac{1}{3}, \frac{8}{7})

range of y=sqrt(1/(x^2+1))range

y = \frac{1}{x ^{2} + 1}

range of f(x)=((x-1))/(x+1)range

f (x) = \frac{( x - 1 )}{x + 1}

Frequently Asked Questions (FAQ)

What is the distance (4,-3),(-2,-3) ?
The distance (4,-3),(-2,-3) is 6