What is the distance (13/3 , 1/7),(1/3 , 8/7) ?

The distance (13/3 , 1/7),(1/3 , 8/7) is square root of 17

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

distance (13/3 , 1/7),(1/3 , 8/7)

distance

17

Decimal

4.12310 \dots

Solution steps

The distance between

(x_{1}, y_{1}), (x_{2}, y_{2})

is:

(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}

The distance between

(\frac{13}{3}, \frac{1}{7})

and

(\frac{1}{3}, \frac{8}{7})

= (\frac{1}{3} - \frac{13}{3})^{2} + (\frac{8}{7} - \frac{1}{7})^{2}

Simplify

= 17

What is the distance (13/3 , 1/7),(1/3 , 8/7) ?
The distance (13/3 , 1/7),(1/3 , 8/7) is square root of 17