What is the domain of f(x)= 1/((x-3)(x-7)) ?

The domain of f(x)= 1/((x-3)(x-7)) is x 7

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domain of f(x)= 1/((x-3)(x-7))

domain

f (x) = \frac{1}{( x - 3 ) ( x - 7 )}

x < 3 or 3 < x < 7 or x > 7

Interval Notation

(- \infty, 3) \cup (3, 7) \cup (7, \infty)

Solution steps

Find undefined (singularity) points:

x = 3, x = 7

The function domain

x < 3 or 3 < x < 7 or x > 7

3 + \frac{1}{x}

f (x) = x^{2} - 5

f (x) = sin (2 x)

f (x) = \frac{1}{3} (x + 4) - 1

f (x) = - 3 x^{2} - 18 x - 24

What is the domain of f(x)= 1/((x-3)(x-7)) ?
The domain of f(x)= 1/((x-3)(x-7)) is x<3\lor 3<x<7\lor x>7