What is the domain of f(x)=sqrt(1/3 (x+4))-1 ?

The domain of f(x)=sqrt(1/3 (x+4))-1 is x>=-4

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domain of f(x)=sqrt(1/3 (x+4))-1

domain

f (x) = \frac{1}{3} (x + 4) - 1

x \geq - 4

Interval Notation

[- 4, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 4

The function domain

x \geq - 4

f (x) = - 3 x^{2} - 18 x - 24

f (x) = x^{3} + 2 x^{2} - 4 x

- x^{2} + 1

f (x) = \frac{x}{x ^{2} - x - 1}

tan (2 x)

What is the domain of f(x)=sqrt(1/3 (x+4))-1 ?
The domain of f(x)=sqrt(1/3 (x+4))-1 is x>=-4