What is the critical f(x)=sin(2x) ?

The critical f(x)=sin(2x) is x= pi/4+pin,x=(3pi)/4+pin

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critical f(x)=sin(2x)

critical points

f (x) = sin (2 x)

x = \frac{π}{4} + πn, x = \frac{3 π}{4} + πn

Solution steps

sin (2 x)

Find where

f^{'} (x)

is equal to zero or undefined

x = \frac{π}{4} + πn, x = \frac{3 π}{4} + πn

Identify critical points not in

f (x)

domain

Domain of

sin (2 x) : - \infty < x < \infty

All critical points are in domain

x = \frac{π}{4} + πn, x = \frac{3 π}{4} + πn

f (x) = \frac{1}{3} (x + 4) - 1

f (x) = - 3 x^{2} - 18 x - 24

f (x) = x^{3} + 2 x^{2} - 4 x

- x^{2} + 1

f (x) = \frac{x}{x ^{2} - x - 1}

What is the critical f(x)=sin(2x) ?
The critical f(x)=sin(2x) is x= pi/4+pin,x=(3pi)/4+pin