What is the d/(dθ)(sin(2θ)) ?

The d/(dθ)(sin(2θ)) is cos(2θ)*2

What is the first d/(dθ)(sin(2θ)) ?

The first d/(dθ)(sin(2θ)) is cos(2θ)*2

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\frac{d}{d θ} (sin (2 θ))

cos (2 θ) \cdot 2

Solution steps

\frac{d}{d θ} (sin (2 θ))

Apply the chain rule:

cos (2 θ) \frac{d}{d θ} (2 θ)

= cos (2 θ) \frac{d}{d θ} (2 θ)

\frac{d}{d θ} (2 θ) = 2

= cos (2 θ) \cdot 2

\frac{( 3 s + 1 )}{s ^{2} + 4 s}

\int \frac{( x ^{3} - x ^{2} + 2 x - 6 )}{x} d x

- 2 x^{2} + 4 x - 4, at x = 3

y^{^{'}} - 7 y = 0

x \to 0 + lim (csc (x))