What is the tangent of-2x^2+4x-4,\at x=3 ?

The tangent of-2x^2+4x-4,\at x=3 is y=-8x+14

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of-2x^2+4x-4,\at x=3

tangent of

- 2 x^{2} + 4 x - 4, at x = 3

y = - 8 x + 14

Solution steps

Find the tangent point:

(3, - 10)

Find the slope of

y = - 2 x^{2} + 4 x - 4 : \frac{d y}{d x} = - 4 x + 4

Compute the slope of

y = - 2 x^{2} + 4 x - 4

x = 3 : m = - 8

Find the line with slope m=

- 8

and passing through

(3, - 10) : y = - 8 x + 14

y = - 8 x + 14

y^{^{'}} - 7 y = 0

x \to 0 + lim (csc (x))

f (t) = e^{t} \cdot cos (t)

t^{2} y^{^{'}} + t y = 4

5^{x}

What is the tangent of-2x^2+4x-4,\at x=3 ?
The tangent of-2x^2+4x-4,\at x=3 is y=-8x+14