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Popular >

t^2y^'+ty=4

Solution

t^{2} y^{^{'}} + t y = 4

Solution

y = \frac{4 ln ( t )}{t} + \frac{c _{1}}{t}

Solution steps

t^{2} y^{'} (t) + t y = 4

Solve linear ODE:

y = \frac{4 ln ( t )}{t} + \frac{c _{1}}{t}

y = \frac{4 ln ( t )}{t} + \frac{c _{1}}{t}

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\int \frac{( 3 x - 5 )}{2 x ^{2} - 6 x + 3} d x

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x y y^{^{'}} = 1 - y^{2}

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\int r^{2} 16 - r^{2} d r

Frequently Asked Questions (FAQ)

What is the solution for t^2y^'+ty=4 ?
The solution for t^2y^'+ty=4 is y=(4ln(t))/t+(c_{1})/t