What is the integral of ((x^3-x^2+2x-6))/x ?

The integral of ((x^3-x^2+2x-6))/x is (x^3)/3-(x^2)/2+2x-6ln|x|+C

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integral of ((x^3-x^2+2x-6))/x

\int \frac{( x ^{3} - x ^{2} + 2 x - 6 )}{x} d x

\frac{x ^{3}}{3} - \frac{x ^{2}}{2} + 2 x - 6 ln ∣ x ∣ + C

Solution steps

\int \frac{x ^{3} - x ^{2} + 2 x - 6}{x} d x

Expand

\frac{x ^{3} - x ^{2} + 2 x - 6}{x} : x^{2} - x + 2 - \frac{6}{x}

= \int x^{2} - x + 2 - \frac{6}{x} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int x^{2} d x - \int x d x + \int 2 d x - \int \frac{6}{x} d x

\int x^{2} d x = \frac{x ^{3}}{3}

\int x d x = \frac{x ^{2}}{2}

\int 2 d x = 2 x

\int \frac{6}{x} d x = 6 ln ∣ x ∣

= \frac{x ^{3}}{3} - \frac{x ^{2}}{2} + 2 x - 6 ln ∣ x ∣

Add a constant to the solution

= \frac{x ^{3}}{3} - \frac{x ^{2}}{2} + 2 x - 6 ln ∣ x ∣ + C

- 2 x^{2} + 4 x - 4, at x = 3

y^{^{'}} - 7 y = 0

x \to 0 + lim (csc (x))

f (t) = e^{t} \cdot cos (t)

t^{2} y^{^{'}} + t y = 4

What is the integral of ((x^3-x^2+2x-6))/x ?
The integral of ((x^3-x^2+2x-6))/x is (x^3)/3-(x^2)/2+2x-6ln|x|+C