What is the tangent of f(x)= 7/x ,\at x=1 ?

The tangent of f(x)= 7/x ,\at x=1 is y=-7x+14

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tangent of f(x)= 7/x ,\at x=1

tangent of

f (x) = \frac{7}{x}, at x = 1

y = - 7 x + 14

Solution steps

Find the tangent point:

(1, 7)

Find the slope of

f (x) = \frac{7}{x} : \frac{df ( x )}{d x} = - \frac{7}{x ^{2}}

Compute the slope of

f (x) = \frac{7}{x}

x = 1 : m = - 7

Find the line with slope m=

- 7

and passing through

(1, 7) : y = - 7 x + 14

y = - 7 x + 14

\frac{\partial}{\partial x} ((x)^{2} y)

\int x^{2} (3 - 2 x) d x

x^{2} - 6 x, 0

\int_{\frac{π}{4}}^{\frac{π}{3}} cot (x) d x

\int x e^{- 7 x} d x

What is the tangent of f(x)= 7/x ,\at x=1 ?
The tangent of f(x)= 7/x ,\at x=1 is y=-7x+14