What is the integral of xe^{-7x} ?

The integral of xe^{-7x} is 1/49 (-7e^{-7x}x-e^{-7x})+C

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integral of xe^{-7x}

\int x e^{- 7 x} d x

\frac{1}{49} (- 7 e^{- 7 x} x - e^{- 7 x}) + C

Solution steps

\int x e^{- 7 x} d x

Apply u-substitution

: \int \frac{e ^{u} u}{49} d u

= \int \frac{e ^{u} u}{49} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{49} \cdot \int e^{u} u d u

Apply Integration By Parts

: e^{u} u - \int e^{u} d u

= \frac{1}{49} (e^{u} u - \int e^{u} d u)

\int e^{u} d u = e^{u}

= \frac{1}{49} (e^{u} u - e^{u})

Substitute back

u = - 7 x

= \frac{1}{49} (e^{- 7 x} (- 7 x) - e^{- 7 x})

Simplify

= \frac{1}{49} (- 7 e^{- 7 x} x - e^{- 7 x})

Add a constant to the solution

= \frac{1}{49} (- 7 e^{- 7 x} x - e^{- 7 x}) + C

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What is the integral of xe^{-7x} ?
The integral of xe^{-7x} is 1/49 (-7e^{-7x}x-e^{-7x})+C