What is the derivative of 2+0.55sin((2pit)/(6.2)) ?

The derivative of 2+0.55sin((2pit)/(6.2)) is 0.55737…cos(1.01341…t)

What is the first derivative of 2+0.55sin((2pit)/(6.2)) ?

The first derivative of 2+0.55sin((2pit)/(6.2)) is 0.55737…cos(1.01341…t)

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derivative of

2 + 0.55 sin (\frac{2 π t}{6.2})

0.55737 \dots cos (1.01341 \dots t)

Solution steps

\frac{d}{d t} (2 + 0.55 sin (\frac{2 π t}{6.2}))

Simplify

2 + 0.55 sin (\frac{2 π t}{6.2}) : 2 + 0.55 sin (1.01341 \dots t)

= \frac{d}{d t} (2 + 0.55 sin (1.01341 \dots t))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (2) + \frac{d}{d t} (0.55 sin (1.01341 \dots t))

\frac{d}{d t} (2) = 0

\frac{d}{d t} (0.55 sin (1.01341 \dots t)) = 0.55737 \dots cos (1.01341 \dots t)

= 0 + 0.55737 \dots cos (1.01341 \dots t)

Simplify

= 0.55737 \dots cos (1.01341 \dots t)

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x \to - 3 - lim (2 x^{2} - 6)

\int \frac{6 x ^{2} + x - 1}{3 x ^{3} - 9 x ^{2} + x - 3} d x

tan (e^{6 t}) + e^{t a n (6 t)}

What is the derivative of 2+0.55sin((2pit)/(6.2)) ?
The derivative of 2+0.55sin((2pit)/(6.2)) is 0.55737…cos(1.01341…t)
What is the first derivative of 2+0.55sin((2pit)/(6.2)) ?
The first derivative of 2+0.55sin((2pit)/(6.2)) is 0.55737…cos(1.01341…t)