What is the derivative of tan(e^{6t})+e^{tan(6t)} ?

The derivative of tan(e^{6t})+e^{tan(6t)} is sec^2(e^{6t})e^{6t}*6+e^{tan(6t)}sec^2(6t)*6

What is the first derivative of tan(e^{6t})+e^{tan(6t)} ?

The first derivative of tan(e^{6t})+e^{tan(6t)} is sec^2(e^{6t})e^{6t}*6+e^{tan(6t)}sec^2(6t)*6

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derivative of

tan (e^{6 t}) + e^{t a n (6 t)}

sec^{2} (e^{6 t}) e^{6 t} \cdot 6 + e^{t a n (6 t)} sec^{2} (6 t) \cdot 6

Solution steps

\frac{d}{d t} (tan (e^{6 t}) + e^{t a n (6 t)})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (tan (e^{6 t})) + \frac{d}{d t} (e^{t a n (6 t)})

\frac{d}{d t} (tan (e^{6 t})) = sec^{2} (e^{6 t}) e^{6 t} \cdot 6

\frac{d}{d t} (e^{t a n (6 t)}) = e^{t a n (6 t)} sec^{2} (6 t) \cdot 6

= sec^{2} (e^{6 t}) e^{6 t} \cdot 6 + e^{t a n (6 t)} sec^{2} (6 t) \cdot 6

\int - e^{2 t} + t e^{t} d t

\int_{0}^{1} x 6 - x^{2} d x

\frac{d}{d x} (sin (x) + \frac{3}{4} cot (x))

\frac{\partial}{\partial x} (cos (x y^{2}))

y^{^{''}} + 4 y = e^{(- t)}

What is the derivative of tan(e^{6t})+e^{tan(6t)} ?
The derivative of tan(e^{6t})+e^{tan(6t)} is sec^2(e^{6t})e^{6t}*6+e^{tan(6t)}sec^2(6t)*6
What is the first derivative of tan(e^{6t})+e^{tan(6t)} ?
The first derivative of tan(e^{6t})+e^{tan(6t)} is sec^2(e^{6t})e^{6t}*6+e^{tan(6t)}sec^2(6t)*6