What is the integral of (x-1)/(2x) ?

The integral of (x-1)/(2x) is 1/2 (x-ln|x|)+C

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integral of (x-1)/(2x)

\int \frac{x - 1}{2 x} d x

\frac{1}{2} (x - ln ∣ x ∣) + C

Solution steps

\int \frac{x - 1}{2 x} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int \frac{x - 1}{x} d x

Expand

\frac{x - 1}{x} : 1 - \frac{1}{x}

= \frac{1}{2} \cdot \int 1 - \frac{1}{x} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \frac{1}{2} (\int 1 d x - \int \frac{1}{x} d x)

\int 1 d x = x

\int \frac{1}{x} d x = ln ∣ x ∣

= \frac{1}{2} (x - ln ∣ x ∣)

Add a constant to the solution

= \frac{1}{2} (x - ln ∣ x ∣) + C

What is the integral of (x-1)/(2x) ?
The integral of (x-1)/(2x) is 1/2 (x-ln|x|)+C