What is area y=e^x,y=e^{-x},[-2,1] ?

The answer to area y=e^x,y=e^{-x},[-2,1] is e^2+(1+e^3+e)/(e^2)-4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

area y=e^x,y=e^{-x},[-2,1]

area

y = e^{x}, y = e^{- x}, [- 2, 1]

e^{2} + \frac{1 + e ^{3} + e}{e ^{2}} - 4

Decimal

6.61055 \dots

Solution steps

Apply the area formula:

\int_{- 2}^{1} e^{x} - e^{- x} d x

Solve

\int_{- 2}^{1} e^{x} - e^{- x} d x : e^{2} + \frac{1 + e ^{3} + e}{e ^{2}} - 4

The area is:

= e^{2} + \frac{1 + e ^{3} + e}{e ^{2}} - 4

What is area y=e^x,y=e^{-x},[-2,1] ?
The answer to area y=e^x,y=e^{-x},[-2,1] is e^2+(1+e^3+e)/(e^2)-4