What is the tangent of f(x)=2x^3,(1,2) ?

The tangent of f(x)=2x^3,(1,2) is y=6x-4

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tangent of f(x)=2x^3,(1,2)

tangent of

f (x) = 2 x^{3}, (1, 2)

y = 6 x - 4

Solution steps

Find the slope of

f (x) = 2 x^{3} : \frac{df ( x )}{d x} = 6 x^{2}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 6

Find the line with slope m=

6

and passing through

(1, 2) : y = 6 x - 4

y = 6 x - 4

What is the tangent of f(x)=2x^3,(1,2) ?
The tangent of f(x)=2x^3,(1,2) is y=6x-4