What is the derivative of y=x^3-9x^2+24x-15 ?

The derivative of y=x^3-9x^2+24x-15 is 3x^2-18x+24

What is the first derivative of y=x^3-9x^2+24x-15 ?

The first derivative of y=x^3-9x^2+24x-15 is 3x^2-18x+24

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

derivative of

y = x^{3} - 9 x^{2} + 24 x - 15

3 x^{2} - 18 x + 24

Solution steps

\frac{d}{d x} (x^{3} - 9 x^{2} + 24 x - 15)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) - \frac{d}{d x} (9 x^{2}) + \frac{d}{d x} (24 x) - \frac{d}{d x} (15)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (9 x^{2}) = 18 x

\frac{d}{d x} (24 x) = 24

\frac{d}{d x} (15) = 0

= 3 x^{2} - 18 x + 24 - 0

Simplify

= 3 x^{2} - 18 x + 24

What is the derivative of y=x^3-9x^2+24x-15 ?
The derivative of y=x^3-9x^2+24x-15 is 3x^2-18x+24
What is the first derivative of y=x^3-9x^2+24x-15 ?
The first derivative of y=x^3-9x^2+24x-15 is 3x^2-18x+24