What is the derivative of (x-1(x^2+x+1)) ?

The derivative of (x-1(x^2+x+1)) is 3x^2

What is the first derivative of (x-1(x^2+x+1)) ?

The first derivative of (x-1(x^2+x+1)) is 3x^2

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Popular >

\frac{d}{d x} ((x - 1) (x^{2} + x + 1))

3 x^{2}

Solution steps

\frac{d}{d x} ((x - 1) (x^{2} + x + 1))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x - 1, g = x^{2} + x + 1

= \frac{d}{d x} (x - 1) (x^{2} + x + 1) + \frac{d}{d x} (x^{2} + x + 1) (x - 1)

\frac{d}{d x} (x - 1) = 1

\frac{d}{d x} (x^{2} + x + 1) = 2 x + 1

= 1 \cdot (x^{2} + x + 1) + (2 x + 1) (x - 1)

Simplify

1 \cdot (x^{2} + x + 1) + (2 x + 1) (x - 1) : 3 x^{2}

= 3 x^{2}

\frac{d}{d x} (- 2 ln (- x))

\frac{sin ( x )}{x}

x \to - 6 - lim (x^{2} + 6)

\frac{d}{d x} (7 x + 2 x)

\frac{d}{d x} (1 + cos (6 x))

What is the derivative of (x-1(x^2+x+1)) ?
The derivative of (x-1(x^2+x+1)) is 3x^2
What is the first derivative of (x-1(x^2+x+1)) ?
The first derivative of (x-1(x^2+x+1)) is 3x^2