What is the derivative of 1+cos(6x) ?

The derivative of 1+cos(6x) is -6sin(6x)

What is the first derivative of 1+cos(6x) ?

The first derivative of 1+cos(6x) is -6sin(6x)

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\frac{d}{d x} (1 + cos (6 x))

- 6 sin (6 x)

Solution steps

\frac{d}{d x} (1 + cos (6 x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (1) + \frac{d}{d x} (cos (6 x))

\frac{d}{d x} (1) = 0

\frac{d}{d x} (cos (6 x)) = - sin (6 x) \cdot 6

= 0 - sin (6 x) \cdot 6

Simplify

= - 6 sin (6 x)

(x^{2} - 1) y^{^{'}} = x y ln (y)

\int_{1}^{\infty} x^{- \frac{4}{3}} d x

\frac{\partial}{\partial x} (e^{- x^{2} - 2 y^{2}})

\int 8 sec (x) (sec (x) - 4 tan (x)) d x

y^{^{''}} + 8 y^{^{'}} + 4 y = t

What is the derivative of 1+cos(6x) ?
The derivative of 1+cos(6x) is -6sin(6x)
What is the first derivative of 1+cos(6x) ?
The first derivative of 1+cos(6x) is -6sin(6x)