What is the derivative of-2ln(-x) ?

The derivative of-2ln(-x) is -2/x

What is the first derivative of-2ln(-x) ?

The first derivative of-2ln(-x) is -2/x

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\frac{d}{d x} (- 2 ln (- x))

- \frac{2}{x}

Solution steps

\frac{d}{d x} (- 2 ln (- x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 2 \frac{d}{d x} (ln (- x))

Apply the chain rule:

\frac{1}{- x} \frac{d}{d x} (- x)

= \frac{1}{- x} \frac{d}{d x} (- x)

\frac{d}{d x} (- x) = - 1

= - 2 \cdot \frac{1}{- x} (- 1)

Simplify

- 2 \cdot \frac{1}{- x} (- 1) : - \frac{2}{x}

= - \frac{2}{x}

\frac{sin ( x )}{x}

x \to - 6 - lim (x^{2} + 6)

\frac{d}{d x} (7 x + 2 x)

\frac{d}{d x} (1 + cos (6 x))

(x^{2} - 1) y^{^{'}} = x y ln (y)

What is the derivative of-2ln(-x) ?
The derivative of-2ln(-x) is -2/x
What is the first derivative of-2ln(-x) ?
The first derivative of-2ln(-x) is -2/x