y^{''}+20y^'+36y=0,y(0)=3,y^'(0)=0

Lösung

y^{^{''}} + 20 y^{^{'}} + 36 y = 0, y (0) = 3, y^{^{'}} (0) = 0

y = (3 + \frac{3}{8}) e^{- 2 t} - \frac{3}{8} e^{- 18 t}

Schritte zur Lösung

y^{''} (t) + 20 y^{'} (t) + 36 y = 0

Solve linear ODE:

y = (3 + \frac{3}{8}) e^{- 2 t} - \frac{3}{8} e^{- 18 t}

y = (3 + \frac{3}{8}) e^{- 2 t} - \frac{3}{8} e^{- 18 t}