What is the solution for y^'=-y+1/(sqrt(y)) ?

The solution for y^'=-y+1/(sqrt(y)) is y=\sqrt[3]{e^{-3t-3c_{1}}+2e^{(-3t-3c_{1})/2}+1}

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y^'=-y+1/(sqrt(y))

y^{^{'}} = - y + \frac{1}{y}

y = 3 e^{- 3 t - 3 c_{1}} + 2 e^{\frac{- 3 t - 3 c _{1}}{2}} + 1

Solution steps

y^{'} (t) = - y + \frac{1}{y}

Solve separable ODE:

y = 3 e^{- 3 t - 3 c_{1}} + 2 e^{\frac{- 3 t - 3 c _{1}}{2}} + 1

y = 3 e^{- 3 t - 3 c_{1}} + 2 e^{\frac{- 3 t - 3 c _{1}}{2}} + 1

What is the solution for y^'=-y+1/(sqrt(y)) ?
The solution for y^'=-y+1/(sqrt(y)) is y=\sqrt[3]{e^{-3t-3c_{1}}+2e^{(-3t-3c_{1})/2}+1}