What is (\partial)/(\partial x)(x-8y+3xy) ?

The answer to (\partial)/(\partial x)(x-8y+3xy) is 3y+1

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(\partial)/(\partial x)(x-8y+3xy)

\frac{\partial}{\partial x} (x - 8 y + 3 x y)

3 y + 1

Solution steps

\frac{\partial}{\partial x} (x - 8 y + 3 x y)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x) - \frac{\partial}{\partial x} (8 y) + \frac{\partial}{\partial x} (3 x y)

\frac{\partial}{\partial x} (x) = 1

\frac{\partial}{\partial x} (8 y) = 0

\frac{\partial}{\partial x} (3 x y) = 3 y

= 1 - 0 + 3 y

Simplify

= 3 y + 1

y = 9 x^{2} - x^{3}, (2, 28)

\int \frac{( cos ( 3 x ) )}{1 + sin ( 3 x )} d x

\int_{0}^{1} 2 π x (12 - 12 x) d x

e^{4}

y^{^{''}} - \frac{9}{t} y^{^{'}} + \frac{34}{t ^{2}} y = 0

What is (\partial)/(\partial x)(x-8y+3xy) ?
The answer to (\partial)/(\partial x)(x-8y+3xy) is 3y+1