What is the solution for y^{''}-9/t y^'+(34)/(t^2)y=0 ?

The solution for y^{''}-9/t y^'+(34)/(t^2)y=0 is y=t^5(c_{1}cos(3ln(t))+c_{2}sin(3ln(t)))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{''}-9/t y^'+(34)/(t^2)y=0

y^{^{''}} - \frac{9}{t} y^{^{'}} + \frac{34}{t ^{2}} y = 0

y = t^{5} (c_{1} cos (3 ln (t)) + c_{2} sin (3 ln (t)))

Solution steps

y^{''} (t) - \frac{9}{t} y^{'} (t) + \frac{34}{t ^{2}} y = 0

Solve linear ODE:

y = t^{5} (c_{1} cos (3 ln (t)) + c_{2} sin (3 ln (t)))

y = t^{5} (c_{1} cos (3 ln (t)) + c_{2} sin (3 ln (t)))

\frac{\partial}{\partial x} (\frac{1}{2 1 + x + y})

\frac{d y}{d x} = \frac{3 x + x y ^{2}}{y + x ^{2} y}

\int \frac{e ^{- x}}{1 - e ^{- 2 x}} d x

\frac{\partial}{\partial x} (x^{2} - y^{2} + x + 1)

\frac{2 x ^{2} + 4 x + 6}{x}

What is the solution for y^{''}-9/t y^'+(34)/(t^2)y=0 ?
The solution for y^{''}-9/t y^'+(34)/(t^2)y=0 is y=t^5(c_{1}cos(3ln(t))+c_{2}sin(3ln(t)))