What is the derivative of-x+9/x+1 ?

The derivative of-x+9/x+1 is -9/(x^2)-1

What is the first derivative of-x+9/x+1 ?

The first derivative of-x+9/x+1 is -9/(x^2)-1

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derivative of

- x + \frac{9}{x} + 1

- \frac{9}{x ^{2}} - 1

Solution steps

\frac{d}{d x} (- x + \frac{9}{x} + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d x}{d x} + \frac{d}{d x} (\frac{9}{x}) + \frac{d}{d x} (1)

\frac{d x}{d x} = 1

\frac{d}{d x} (\frac{9}{x}) = - \frac{9}{x ^{2}}

\frac{d}{d x} (1) = 0

= - 1 - \frac{9}{x ^{2}} + 0

Simplify

= - \frac{9}{x ^{2}} - 1

\frac{\partial}{\partial x} (x - 8 y + 3 x y)

y = 9 x^{2} - x^{3}, (2, 28)

\int \frac{( cos ( 3 x ) )}{1 + sin ( 3 x )} d x

\int_{0}^{1} 2 π x (12 - 12 x) d x

e^{4}

What is the derivative of-x+9/x+1 ?
The derivative of-x+9/x+1 is -9/(x^2)-1
What is the first derivative of-x+9/x+1 ?
The first derivative of-x+9/x+1 is -9/(x^2)-1