What is the tangent of y=x^3-12x,(1,-11) ?

The tangent of y=x^3-12x,(1,-11) is y=-9x-2

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tangent of y=x^3-12x,(1,-11)

tangent of

y = x^{3} - 12 x, (1, - 11)

y = - 9 x - 2

Solution steps

Find the slope of

y = x^{3} - 12 x : \frac{d y}{d x} = 3 x^{2} - 12

Compute the slope of

y = x^{3} - 12 x

(1, - 11) : m = - 9

Find the line with slope m=

- 9

and passing through

(1, - 11) : y = - 9 x - 2

y = - 9 x - 2

- x + \frac{9}{x} + 1

\frac{\partial}{\partial x} (x - 8 y + 3 x y)

y = 9 x^{2} - x^{3}, (2, 28)

\int \frac{( cos ( 3 x ) )}{1 + sin ( 3 x )} d x

\int_{0}^{1} 2 π x (12 - 12 x) d x

What is the tangent of y=x^3-12x,(1,-11) ?
The tangent of y=x^3-12x,(1,-11) is y=-9x-2