What is the derivative of (6x+1^2) ?

The derivative of (6x+1^2) is 12(6x+1)

What is the first derivative of (6x+1^2) ?

The first derivative of (6x+1^2) is 12(6x+1)

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\frac{d}{d x} ((6 x + 1)^{2})

12 (6 x + 1)

Solution steps

\frac{d}{d x} ((6 x + 1)^{2})

Apply the chain rule:

2 (6 x + 1) \frac{d}{d x} (6 x + 1)

= 2 (6 x + 1) \frac{d}{d x} (6 x + 1)

\frac{d}{d x} (6 x + 1) = 6

= 2 (6 x + 1) \cdot 6

Simplify

= 12 (6 x + 1)

y^{^{''}} - 25 y = 0

y^{^{'}} + 27 y = \frac{1}{x ^{2}}

\int \frac{x}{( 1 - x ^{2} ) ^{\frac{1}{2}}} d x

x^{4} + y^{3} x^{5} + 4 y^{^{'}} = 0

n = 1 \sum \infty \frac{2}{3 ^{n - 1}}

What is the derivative of (6x+1^2) ?
The derivative of (6x+1^2) is 12(6x+1)
What is the first derivative of (6x+1^2) ?
The first derivative of (6x+1^2) is 12(6x+1)