What is the solution for y^'+27y= 1/(x^2) ?

The solution for y^'+27y= 1/(x^2) is y=-1/x+(27\Ei(27x))/(e^{27x)}+(c_{1})/(e^{27x)}

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y^'+27y= 1/(x^2)

y^{^{'}} + 27 y = \frac{1}{x ^{2}}

y = - \frac{1}{x} + \frac{27 Ei ( 27 x )}{e ^{27 x}} + \frac{c _{1}}{e ^{27 x}}

Solution steps

y^{'} (x) + 27 y = \frac{1}{x ^{2}}

Solve linear ODE:

y = - \frac{1}{x} + \frac{27 Ei ( 27 x )}{e ^{27 x}} + \frac{c _{1}}{e ^{27 x}}

y = - \frac{1}{x} + \frac{27 Ei ( 27 x )}{e ^{27 x}} + \frac{c _{1}}{e ^{27 x}}

\int \frac{x}{( 1 - x ^{2} ) ^{\frac{1}{2}}} d x

x^{4} + y^{3} x^{5} + 4 y^{^{'}} = 0

n = 1 \sum \infty \frac{2}{3 ^{n - 1}}

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\int_{1}^{2} \frac{1}{x ^{2}} - \frac{4}{x ^{3}} d x

What is the solution for y^'+27y= 1/(x^2) ?
The solution for y^'+27y= 1/(x^2) is y=-1/x+(27\Ei(27x))/(e^{27x)}+(c_{1})/(e^{27x)}