What is the integral of x/((1-x^2)^{1/2)} ?

The integral of x/((1-x^2)^{1/2)} is (x^2)/((1-x^2)^{1/2)}-1/((1-x^2)^{1/2)}+C

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integral of x/((1-x^2)^{1/2)}

\int \frac{x}{( 1 - x ^{2} ) ^{\frac{1}{2}}} d x

\frac{x ^{2}}{( 1 - x ^{2} ) ^{\frac{1}{2}}} - \frac{1}{( 1 - x ^{2} ) ^{\frac{1}{2}}} + C

Solution steps

\int \frac{x}{( 1 - x ^{2} ) ^{\frac{1}{2}}} d x

Apply Integration By Parts

: \frac{x ^{2}}{( 1 - x ^{2} ) ^{\frac{1}{2}}} - \int \frac{x}{( 1 - x ^{2} ) ^{\frac{3}{2}}} d x

= \frac{x ^{2}}{( 1 - x ^{2} ) ^{\frac{1}{2}}} - \int \frac{x}{( 1 - x ^{2} ) ^{\frac{3}{2}}} d x

\int \frac{x}{( 1 - x ^{2} ) ^{\frac{3}{2}}} d x = \frac{1}{( 1 - x ^{2} ) ^{\frac{1}{2}}}

= \frac{x ^{2}}{( 1 - x ^{2} ) ^{\frac{1}{2}}} - \frac{1}{( 1 - x ^{2} ) ^{\frac{1}{2}}}

Add a constant to the solution

= \frac{x ^{2}}{( 1 - x ^{2} ) ^{\frac{1}{2}}} - \frac{1}{( 1 - x ^{2} ) ^{\frac{1}{2}}} + C

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What is the integral of x/((1-x^2)^{1/2)} ?
The integral of x/((1-x^2)^{1/2)} is (x^2)/((1-x^2)^{1/2)}-1/((1-x^2)^{1/2)}+C