x^4+y^3sqrt(x^5+4)y^'=0

Lösung

x^{4} + y^{3} x^{5} + 4 y^{^{'}} = 0

y = 4 - \frac{8}{5} x^{5} + 4 + c_{1}, y = - 4 - \frac{8}{5} x^{5} + 4 + c_{1}

Schritte zur Lösung

x^{4} + y^{3} x^{5} + 4 y^{'} (x) = 0

Solve separable ODE:

y = 4 - \frac{8}{5} x^{5} + 4 + c_{1}, y = - 4 - \frac{8}{5} x^{5} + 4 + c_{1}

y = 4 - \frac{8}{5} x^{5} + 4 + c_{1}, y = - 4 - \frac{8}{5} x^{5} + 4 + c_{1}

n = 1 \sum \infty \frac{2}{3 ^{n - 1}}

\int 5 cot^{4} (x) d x

\int_{1}^{2} \frac{1}{x ^{2}} - \frac{4}{x ^{3}} d x

\frac{d}{d t} (f (t))

\frac{d}{d x} (\frac{5 x ^{2} - 3 x ^{5}}{- x})