What is the derivative of 3x+6/x ?

The derivative of 3x+6/x is 3-6/(x^2)

What is the first derivative of 3x+6/x ?

The first derivative of 3x+6/x is 3-6/(x^2)

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\frac{d}{d x} (3 x + \frac{6}{x})

3 - \frac{6}{x ^{2}}

Solution steps

\frac{d}{d x} (3 x + \frac{6}{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x) + \frac{d}{d x} (\frac{6}{x})

\frac{d}{d x} (3 x) = 3

\frac{d}{d x} (\frac{6}{x}) = - \frac{6}{x ^{2}}

= 3 - \frac{6}{x ^{2}}

\frac{d}{d x} (\frac{1}{2} sin (x))

\int (e^{x} - 3)^{4} e^{x} d x

\int_{2}^{3} 3 x 2 x^{2} - 1 d x

x \to 0 lim ((2 x + 1) (x - 3))

\frac{8}{x}

What is the derivative of 3x+6/x ?
The derivative of 3x+6/x is 3-6/(x^2)
What is the first derivative of 3x+6/x ?
The first derivative of 3x+6/x is 3-6/(x^2)