What is the derivative of 8/x ?

The derivative of 8/x is -8/(x^2)

What is the first derivative of 8/x ?

The first derivative of 8/x is -8/(x^2)

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derivative of

\frac{8}{x}

- \frac{8}{x ^{2}}

Solution steps

\frac{d}{d x} (\frac{8}{x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 8 \frac{d}{d x} (\frac{1}{x})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 8 \frac{d}{d x} (x^{- 1})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 8 (- 1 \cdot x^{- 1 - 1})

Simplify

8 (- 1 \cdot x^{- 1 - 1}) : - \frac{8}{x ^{2}}

= - \frac{8}{x ^{2}}

\frac{\partial}{\partial x} (vx)

y^{^{'}} - 2 y = - 3 e^{t}

x \to - 3 lim (\frac{8}{x + 3})

\int_{0}^{2} \frac{1}{1 + e ^{2 x}} d x

x \to - \infty lim (- 5 x^{3})